Question

^7Log3=P, ^3Log4=Q

^12Log63=?

Answer 1

7'log 3 = p
3'log 4 = q
7'log 4 = pq

12'log 63
= 3'log 63 / 3'log 12
= (3'log 3^2 + 3'log 7) / (3'log 4 + 3'log 3)
= (2 + (1/p)) / (1 + q)
= (1 + 2p) / (p + pq)