Question

Diketahui log 2=0,3010;log 3=0,4771 dan log 7=0,8451 tentukan:
a.log 18
b.log 21
c.log 10,5
d,log 1/7

Answer 1

diketahui log 2 = 0.03010 log 3 = 0.4771 dan log 7 = 0.8451
tent
log 18 = log (3² x 2)
= 2log3 + 2log2
= 2 x 0.4771 + 0.3010
= 1.2552

log 21 = log (7 x 3)
=log 7 + log3
=0.8451 + 0.4771
=1.3222

log 10.5 =log 7 x 3 per 2
log 7 + log 3 - log 2
= 0.8451 + 0.47771 - 0.3010
=
tandain jawaban terbaik yaaaa

Answer 2

A. log 18 : Log(2x3x3) -> Log 2 ditambah log 3 ditambah log 3
-> 0,3010 ditambah 0,4771 ditambah 0,4771 -> 1,2552
b. Log 21 : Log ( 3x7) -> Log 3 ditambah Log 7 -> 0,4771 ditmbah 0,8451 -> 1,3222