Hitunglah volume kerucut yg luas selimutnya 2.200 cm2 dan luas alas 616 cm2! (Π= 22/7)
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Lselimut = π r s
2200 = 22/7 . r . s
r.s = 2200 . 7/22
r.s = 700
Lalas = π r²
616 = 22/7 r²
r² = 616 . 7/22
r² = 196
r = 14 cm
r.s = 700
14.s = 700
s = 50 cm
t = √(s²-r²) -->phytagoras
t = √2500 - 196
t = 48 cm
L = 1/3 . π . r². t
L = 1/3 . 22/7 . 14² . 48
L = 9856cm³