Question

Tentukn penyelesaian pertidaksamaan berikut dg caranya yaa

a) 3(x+2) < 6(3x-4) < 4(x +8)
b) 1/4(4x-4)-3/7(3x+2) ≤ -2

Answer 1

A) 3(x+2) < 6(3x-4) < 4(x +8)
3x + 6 < 18x - 24 < 4x + 8
3x - 18x - 4x < 0 < 8 + 24 - 6
-19x < 0 < 26
x < 0 < 26 : -19

b) 1/4(4x-4)-3/7(3x+2) ≤ -2 [dikali KPK 4 dan 7]
7(4x-4)-12(3x+2) <= -2
28x-28-36x-24 <= -2
-8x-52 <= -2
-8x <= 50
x => 50 : -8 [tandanya dibalik karna dibagi negatif]

Answer 2

A. 3(x+2) < 6(3x-4) < 4(x+8) 3x+6<18x-24 3x-18x<-24-6 -15x<-30 x>30/15 x>2 6(3x-4)<4(x+8) 18x-24<4x+32 18x-4x<32+24 14x<56 x<56/14 x<4 (2