Question

7√27+ 3√12 - √300 =
3 log 81 + 2 log 32 -5 log 125=

Answer 1

7√27+3√12-√300
=7.3√3+3.2√3-10√3
=21√3+6√3-10√3
=(21+6-10)√3
=17√3

3log81+2log32-5log125
=4+5+3
=12

Answer 2

7√27+ 3√12 - √300
=7√9√3 + 3√4√3 - √100√3
=7.3√3 + 3.2√3 - 10√3
=21√3 + 6√3 - 10√3
=(21+6-10)√3
=17√3

³log 81 + ²log 32 - ^5log 125
=³log 3⁴ + ²log 2^5 - ^5log 5³
=4 ³log 3 + 5 ²log 2 - 3 ^5log 5
=4.1 + 5.1 - 3.1
=4+5-3
=6