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a+3c=75
Obteniendo un sistema de ecuaciones lineales:
a/4 = c/7 ..........4c=7a..........3c=21a/4
a+3c=75
Reemplazando:
a+3c=75................a + 21a/4 = 75
Resolviendo la ecuación:
4a/4 + 21a/4 = 75
25a = 25*3*4
a= 12
Ahora:
a/4 = b/5
12/4 = 3 = b/5
Luego b= 15