Question

Volume suatu kerucut 462cm³. jika tinggi kerucut 9cm dan Π / phi 22/7 , tentukan panjang jari jari alas kerucut!

Answer 1

V kerucut = 462
1/3.phi.r².t = 462
1/3.22/7.r².9 = 462
3.22/7.r² = 462
66/7.r² = 462
r² = 462 : 66/7
r² = 462 . 7/66
r² = 7.7
r² = 49
r = √49
r = 7 cm