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r = √154 : 22/7
r = √49
r = 7 cm
s kerucut = akar dari t² + r²
s = √24² + 7²
s = √576+49
s= √625
s = 25 cm
a) Luas selimut kerucut = π x r x s
Luas selimut kerucut = 22/7 x 7 x 25
Luas selimut kerucut = 22 x 25
Luas selimut kerucut = 550 cm²
b) Luas permukaan kerucut = Luas alas + Luas selimut
= 154 cm² + 550 cm²
= 704 cm²