Diameter alas kerucut 42cm dan panjang garis pelukis 29cm,(pi=22/7) tentukan a) tinggi kerucut b) luas selimut kerucut c) luas alas kerucut d) luas permukaan kerucut e) volume kerucut
A. t = √29²-(42/2)² = √841-441 = √400 = 20 cm b. ls = 22/7 x 21 x 29 = 66 x 29 = 1.914 cm² c. la = 22/7 x 21² = 66 x 21 = 1.386 cm² d. lp = 22/7 x 21 x (21+29) = 66 x 50 = 3.300 cm² e. v = 22/7 x 21² x 20/3 = 22 x 420 = 9.240 cm³
Verified answer
A. t = √29²-(42/2)² = √841-441 = √400 = 20 cmb. ls = 22/7 x 21 x 29 = 66 x 29 = 1.914 cm²
c. la = 22/7 x 21² = 66 x 21 = 1.386 cm²
d. lp = 22/7 x 21 x (21+29) = 66 x 50 = 3.300 cm²
e. v = 22/7 x 21² x 20/3 = 22 x 420 = 9.240 cm³