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******Primero******
(a+1)x+(a-1)y=8
(a+1)(-2) + (a-1)(5) = 8
-2a - 2 + 5a -5 = 8
5a - 2a -5 - 2 = 8
3a - 7 = 8
3a = 15
a = 5.
****** Segundo******
(2a+b)x+(3a-2b)y=-17
[2(5)+b](-2)+[3(5)-2b](5) = -17
(10+b)(-2) + (15-2b)(5) = -17
-20 -2b + 75 -10b = -17
75 - 20 -2b -10b = -17
55 + 17 = 2b + 10b
72 = 12b
6 = b
Entonces...
a + b = 5 + 6 = 11.