Oblicz zawartość procentowa wody w siarczanie (VI) sodu - woda (1/7)- Na2SO4 *7 H2O
Na₂SO₄ * 7 H₂O
Masa roztworu wynosi 142 g/mol + 126 g/mol= 268 g/mol
Masa wody wynosi 126 g/mol
Cp= mw/ mr * 100%= 47%
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Na₂SO₄ * 7 H₂O
Masa roztworu wynosi 142 g/mol + 126 g/mol= 268 g/mol
Masa wody wynosi 126 g/mol
Cp= mw/ mr * 100%= 47%