Diketahui luas selimut tabung 528 cm² tinggi 12 cm dan phi 22/7 ,maka panjang diameter alas tabung itu adalah
yahyajember
Luas selimut = 528 cm² p x l = 528 cm² 12 cm x l = 528 cm² lebar = 528 cm² : 12 cm lebar = 44 cm
lebar selimut = keliling alas keliling alas = 44 cm 22/7 x diameter = 44 cm diameter = 44 cm : 22/7 diameter = 44 cm x 7/22 diameter = 2 cm x 7 diameter = 14 cm
p x l = 528 cm²
12 cm x l = 528 cm²
lebar = 528 cm² : 12 cm
lebar = 44 cm
lebar selimut = keliling alas
keliling alas = 44 cm
22/7 x diameter = 44 cm
diameter = 44 cm : 22/7
diameter = 44 cm x 7/22
diameter = 2 cm x 7
diameter = 14 cm
528 = 2 x 22/7 x r x 12
528 = 2 x 22 x 12 x r
7
528 = 528 x r
7
528 x 7 = r
528
3696 = r
528
7 = r
r = 7 cm