PEMBAHASAN
Bangun Datar
Lingkaran
P pusat lingkaran
∠BPC = ∠CPD = 2 × 30° = 60°
∆ABD dan ∆BPD
aturan cosinus
BD² = BD²
r² + r² - 2.r.r cos BPD = AB² + AD² - 2.AB.AD cos BAD
r² + r² - 2r² cos 120° = 9² + 6² - 2.9.6 cos 60°
3r² = 63
r² = 21
BD = √(3r²) = r√3
∆BPC dan ∆CPD sama sisi
BC = CD = r
segi empat tali busur ABCD
berlaku :
AC × BD = AB × DC + BC × AD
r√3 × AC = 9r + 6r
AC √3 = 15
AC = 5√3 cm
Luas tembereng BC dengan sudut pusat 60°
= 1/6 πr² - 1/4 r² √3
Luas daerah ABC
= luas ∆ABC + luas tembereng BC
= 1/2 × AB × AC sin 30° + 1/6 πr² - 1/4 r² √3
= 45/4 √3 + 11 - 21/4 √3
= 11 + 6√3 cm²
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Verified answer
PEMBAHASAN
Bangun Datar
Lingkaran
P pusat lingkaran
∠BPC = ∠CPD = 2 × 30° = 60°
∆ABD dan ∆BPD
aturan cosinus
BD² = BD²
r² + r² - 2.r.r cos BPD = AB² + AD² - 2.AB.AD cos BAD
r² + r² - 2r² cos 120° = 9² + 6² - 2.9.6 cos 60°
3r² = 63
r² = 21
BD = √(3r²) = r√3
∆BPC dan ∆CPD sama sisi
BC = CD = r
segi empat tali busur ABCD
berlaku :
AC × BD = AB × DC + BC × AD
r√3 × AC = 9r + 6r
AC √3 = 15
AC = 5√3 cm
Luas tembereng BC dengan sudut pusat 60°
= 1/6 πr² - 1/4 r² √3
Luas daerah ABC
= luas ∆ABC + luas tembereng BC
= 1/2 × AB × AC sin 30° + 1/6 πr² - 1/4 r² √3
= 45/4 √3 + 11 - 21/4 √3
= 11 + 6√3 cm²