Penjelasan dengan langkah-langkah:
LPbR
LP.Tabung tanpa tutup
= πr² + 2πrt
= πr(r+2t)
= 22/7 × 10,5(10,5+2(15))
= 22 × 1,5 (40,5)
= 33 (40,5)
= 1336,5 cm²
Luas seng yang diperlukan Budi adalah 1336,5 cm²
..
[tex]\begin{aligned} Luas~Seng &= 22/7 × 10,5 × (10,5 + 2(15)) \\&= 33 × (10,5 + 30) \\&= 33 × 40,5 \\&= 1336,5~cm² \end{aligned}[/tex]
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 01 - 04 - 2023}}[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Penjelasan dengan langkah-langkah:
LPbR
LP.Tabung tanpa tutup
= πr² + 2πrt
= πr(r+2t)
= 22/7 × 10,5(10,5+2(15))
= 22 × 1,5 (40,5)
= 33 (40,5)
= 1336,5 cm²
Luas seng yang diperlukan Budi adalah 1336,5 cm²
Bangun Ruang Sisi Lengkung
[Tabung Tanpa Tutup]
..
[tex]\begin{aligned} Luas~Seng &= 22/7 × 10,5 × (10,5 + 2(15)) \\&= 33 × (10,5 + 30) \\&= 33 × 40,5 \\&= 1336,5~cm² \end{aligned}[/tex]
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 01 - 04 - 2023}}[/tex]