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a . f(x) =1/3x+6
y=1/3x+6
y=1/3x+18/3
3y=x+8
3y-8=x---->maka inversnya f(x)⁻¹=3x-8
b. f(x)=5x-1/ 6x+2
y=30x/6-1/6+12/6
6y =30x-1+12
6y =30x+11
6y-11=30x
x = 6y/30-11/30
x = 1/5y-11/30 --->maka inversnya f(x)⁻¹=1/5x-11/30
c . diket: f(x )=x+3, (f°g)(x) =x²+6x-5
(f°g)(x) =f(g(x))
x²+6x-5= g(x)+3
x²+6x-8= g(x)