[tex]x + \frac{2}{6} = \frac{8}{6} \\ x + \frac{1}{3} = \frac{4}{3} \\ 3(x + \frac{1}{3} ) = 3 \times \frac{4}{3} \\ 3x + 1 = 4 \\ 3x = 4 - 1 \\ 3x = 3 \\ x = 1[/tex]
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[tex]x + \frac{2}{6} = \frac{8}{6} \\ x + \frac{1}{3} = \frac{4}{3} \\ 3(x + \frac{1}{3} ) = 3 \times \frac{4}{3} \\ 3x + 1 = 4 \\ 3x = 4 - 1 \\ 3x = 3 \\ x = 1[/tex]