Tentukan nilai dari p pada perbandingan perbandingan berikut c.p+1/4=96/120? d.5/3=75/6p-3? please jawab donk besok di kumpul
subebe
C. p + 1/4 = 96/120 p = 96/120 - 1/4 p = 96/120 - 30/120 p = 66/120 p = 11/20 d. 5/3 = 75/(6p-3) 5(6p-3) = 3 x 75 30p - 15 = 225 30p = 240 p = 6
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wiwiyunianti
C. p + 1/4 = 96/120 p = 96/120 - 1/4 (pindah ruas) p = 96/120 - 30/120 (samakan penyebutnya) p = 66/120 = 11/20 (di sederhanakan)
d. 5/3 =75/6p - 3 75/6p = 5/3 + 3 75/6p = 14/3 p = 14/3 :75/6 p = 14/3 x 6/75 p = 28/75
p = 96/120 - 1/4
p = 96/120 - 30/120
p = 66/120
p = 11/20
d. 5/3 = 75/(6p-3)
5(6p-3) = 3 x 75
30p - 15 = 225
30p = 240
p = 6
p = 96/120 - 1/4 (pindah ruas)
p = 96/120 - 30/120 (samakan penyebutnya)
p = 66/120 = 11/20 (di sederhanakan)
d. 5/3 =75/6p - 3
75/6p = 5/3 + 3
75/6p = 14/3
p = 14/3 :75/6
p = 14/3 x 6/75
p = 28/75
semoga benar dan membantu yaa