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6ax + 3a + 2x + 1
3a (2x + 1) + (2x + 1)
(2x + 1) (3a + 1)
Respuesta :
(2x + 1) (3a + 1)
Caso.
Factor comun por agrupacion de terminos.
6ax + 3a + 1 + 2x = Agrupas
(6ax + 3a) + (1 + 2x) = Sacas factor comun 3a
3a(2x + 1) + ( 1 + 2x) = Sacas factor comun (2x + 1)
(2x + 1)(3a + 1)
Respuesta.
(2x + 1)(3a + 1)