Nyatakan ke dalam bentuk akar !
a . 7pangkat3/2
b . 64pangkat-2/3
c. x pangkat-5/4
d. 1/xpangkat-1/6
a . 7pangkat3/2
b . 64pangkat-2/3
c. x pangkat-5/4
d. 1/xpangkat-1/6
Reyznha
![a) \sqrt{7^3} = 7 \sqrt{7} \\ b) \frac{1}{ \sqrt[3]{64} } \\ c) \frac{1}{ \sqrt[4]{x^{-4}} } \\ d) \frac{1}{ \frac{1}{ \sqrt[6]{x} } } = \sqrt[6]{x}](https://tex.z-dn.net/?f=a%29+%5Csqrt%7B7%5E3%7D+%3D+7+%5Csqrt%7B7%7D+%5C%5C+b%29+%5Cfrac%7B1%7D%7B+%5Csqrt%5B3%5D%7B64%7D+%7D+%5C%5C+c%29++%5Cfrac%7B1%7D%7B+%5Csqrt%5B4%5D%7Bx%5E%7B-4%7D%7D+%7D+%5C%5C+d%29++%5Cfrac%7B1%7D%7B+%5Cfrac%7B1%7D%7B+%5Csqrt%5B6%5D%7Bx%7D+%7D+%7D+%3D++%5Csqrt%5B6%5D%7Bx%7D+ "a) \sqrt{7^3} = 7 \sqrt{7} \\ b) \frac{1}{ \sqrt[3]{64} } \\ c) \frac{1}{ \sqrt[4]{x^{-4}} } \\ d) \frac{1}{ \frac{1}{ \sqrt[6]{x} } } = \sqrt[6]{x}")
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hermawansusanto
itu car cara ngetik gitu gmn mbak?
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