Question

Soal Logaritma
4^log 16 - 4^log 1/64 + 4^log akar 128

Answer 1

⁴log 16 - ⁴log 64 + ⁴log √128 
= ⁴log 16√128 / 64
= ⁴log (1/4)√128
= ⁴log √128/16
= ⁴log √2⁷/2⁴
= ⁴log 2^(3/2)
= (3/2) / 2
= 3/4