Jawaban:
C. 6 V
Penjelasan:
Paralelkan 6Ω dan 3Ω
1/Rp = ⅙ + ⅓
1/Rp = ⅙ + 2/6
1/Rp = 3/6
Rp = 2 Ω
Hambatan total rangkaian :
Rtot = 2 Ω + 2 Ω
Rtot = 4 Ω
Arus rangkaian :
I = V/R
I = 12/4
I = 3 A
Arus yang melewati R1 = 3 A
Beda potensial pada R1 :
V1 = I . R
V1 = 3 . 2
V1 = 6 V
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawaban:
C. 6 V
Penjelasan:
Paralelkan 6Ω dan 3Ω
1/Rp = ⅙ + ⅓
1/Rp = ⅙ + 2/6
1/Rp = 3/6
Rp = 2 Ω
Hambatan total rangkaian :
Rtot = 2 Ω + 2 Ω
Rtot = 4 Ω
Arus rangkaian :
I = V/R
I = 12/4
I = 3 A
Arus yang melewati R1 = 3 A
Beda potensial pada R1 :
V1 = I . R
V1 = 3 . 2
V1 = 6 V