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molaritas = n/v = 10/500 = 0,02 = 10^-2
[H+] = x [HNO3]
[H+] = 1 (10^-2)
[H+] = 10^-2
pH = - log [H+]
pH= - log (10^-2)
pH = 2
= 0,1×2
= 0,2