[tex](x - \frac{2}{3} )(x + \frac{1}{6} ) = \\ \\ {x}^{2} + \frac{1}{6} x - \frac{2}{3} x - \frac{1}{9} \\ \\ \bf = {x}^{2} - \frac{1}{2} x - \frac{1}{9} [/tex]
Respuesta:
(x- 2/3) (x+ 1/6) =
x²+ 1/6× - 2/3x - 1/9
= x² - 1/2× - 1/9
Atte
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[tex](x - \frac{2}{3} )(x + \frac{1}{6} ) = \\ \\ {x}^{2} + \frac{1}{6} x - \frac{2}{3} x - \frac{1}{9} \\ \\ \bf = {x}^{2} - \frac{1}{2} x - \frac{1}{9} [/tex]
Respuesta:
(x- 2/3) (x+ 1/6) =
x²+ 1/6× - 2/3x - 1/9
= x² - 1/2× - 1/9
Atte
Rojero