Question

2log 256 +2log 1/6 - 2log 64 = ? mohon bantu ya kawan

Answer 1

2log256 + 2log1/6 - 2log64
= 2log2^8 + 2log6^-1 - 2log2^6
= 2log2^8 + 2log(2.3)^-1 - 2log2^6
= 8+(-1)+6 . 2log2 + 2log2 + 2log3 - 2log2
= 13 . 1+1-1+2log3
= 13 2log3

kalau gk slh sperti itu

Answer 2

=  ²log 256 + ²log 1 - ²log 6 - ²log64
=  8 + 0 - ²log 2.3 - 6
=  ²log 2 + ²log 3 + 2
= 1 + ²log 3 + 2
=  3 + ²log 3