Question

5√(x+y)^2
5√(x+7)^7
ME Pueden resolver este ejercicio

Answer 1

Respuesta:

[tex]\sqrt[5]{\left(x+y\right)^2}\\\\=\left(\left(x+y\right)^2\right)^{\frac{1}{5}}\\\\=\left(x+y\right)^{2\cdot \frac{1}{5}}\\\\=\left(x+y\right)^{\frac{2}{5}}[/tex]

[tex]\sqrt[5]{\left(x+7\right)^7}\\\\\\=\sqrt[5]{\left(x+7\right)^5}\sqrt[5]{\left(x+7\right)^2}\\=\sqrt[5]{\left(x+7\right)^5}\sqrt[5]{\left(x+7\right)^2}\\\\=\left(x+7\right)\sqrt[5]{\left(x+7\right)^2}\\\\=\sqrt[5]{\left(x+7\right)^2}\left(x+7\right)\\\\=\left(x+7\right)\sqrt[5]{\left(x+7\right)^2}[/tex]