Respuesta:
Explicación paso a paso:
[tex]\left(\frac{7x^2-5}{2x+2}\right)\left(\frac{2}{5x+3}\right)\\\\\\=\frac{7x^2-5}{2x+2}\times \frac{2}{5x+3}\\\\\\=\frac{\left(7x^2-5\right)\times \:2}{\left(2x+2\right)\left(5x+3\right)}\\\\\\=\frac{7x^2-5}{\left(x+1\right)\left(5x+3\right)}[/tex]
asi queda.. saludos!
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Respuesta:
Explicación paso a paso:
[tex]\left(\frac{7x^2-5}{2x+2}\right)\left(\frac{2}{5x+3}\right)\\\\\\=\frac{7x^2-5}{2x+2}\times \frac{2}{5x+3}\\\\\\=\frac{\left(7x^2-5\right)\times \:2}{\left(2x+2\right)\left(5x+3\right)}\\\\\\=\frac{7x^2-5}{\left(x+1\right)\left(5x+3\right)}[/tex]
asi queda.. saludos!