Respuesta:
[tex]x=\frac{180}{23},\:y=\frac{63}{23}[/tex]
Explicación paso a paso:
[tex]\begin{bmatrix}5x+12y=72\\ 18x-12y=108\end{bmatrix}[/tex]
[tex]\mathrm{Sustituir\:}x=\frac{72-12y}{5}[/tex]
[tex]\begin{bmatrix}18\cdot \frac{72-12y}{5}-12y=108\end{bmatrix}[/tex]
[tex]\begin{bmatrix}\frac{1296-276y}{5}=108\end{bmatrix}[/tex]
[tex]y=\frac{63}{23}[/tex]
[tex]\mathrm{Para\:}x=\frac{72-12y}{5}[/tex]
[tex]\mathrm{Sustituir\:}y=\frac{63}{23}[/tex]
[tex]x=\frac{72-12\cdot \frac{63}{23}}{5}[/tex]
[tex]x=\frac{180}{23}[/tex]
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Respuesta:
[tex]x=\frac{180}{23},\:y=\frac{63}{23}[/tex]
Explicación paso a paso:
[tex]\begin{bmatrix}5x+12y=72\\ 18x-12y=108\end{bmatrix}[/tex]
[tex]\mathrm{Sustituir\:}x=\frac{72-12y}{5}[/tex]
[tex]\begin{bmatrix}18\cdot \frac{72-12y}{5}-12y=108\end{bmatrix}[/tex]
[tex]\begin{bmatrix}\frac{1296-276y}{5}=108\end{bmatrix}[/tex]
[tex]y=\frac{63}{23}[/tex]
[tex]\mathrm{Para\:}x=\frac{72-12y}{5}[/tex]
[tex]\mathrm{Sustituir\:}y=\frac{63}{23}[/tex]
[tex]x=\frac{72-12\cdot \frac{63}{23}}{5}[/tex]
[tex]x=\frac{180}{23}[/tex]
[tex]x=\frac{180}{23},\:y=\frac{63}{23}[/tex]