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-1/f = 1/So + 1/S’
-1/10 =1/15+1/s’
-1/s’ = 1/15 + 1/10
-1/s’ =2/30 + 3/30
-1/s’= 5/30
s’ = -30/5 = -6 cm
jarak banyangan 6 cm dibelakang cermin
perbesarannya = S'/So= 6/15 = 0.4 kali
tingginya = M x To = 0,4 x 5 = 2 cm
S' = jarak bayangan
So = Jarak benda
To = Tinggi benda
M = perbesaran
F= Titik api/fokus