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Verified answer
Integral (1/5 x^3 - 7x^2) dx= 1/((3+1)×5) x^3+1 - 7/(2+1) x^2+1 + C
= 1/(4×5) x^4 - 7/3 x^3 + C
= 1/20 x^4 - 7/3 x^3 + C