Hola
[tex]5q = 5 \\ \\ q = \frac{5}{5} \\ \\ q = 1 \\ \\ 5(1) = 5 \\ \\ 5 = 5[/tex]
Respecto a tu pregunta
x-1(3x)=7(x+2)
x - 3x + x = 7x + 14
2x - 3 = 7x + 14
2x - 7x = 14 + 3
-5x = 17
x = ¹⁷/-5
nota: avísame si tenés dudas
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Hola
[tex]5q = 5 \\ \\ q = \frac{5}{5} \\ \\ q = 1 \\ \\ 5(1) = 5 \\ \\ 5 = 5[/tex]
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Respecto a tu pregunta
x-1(3x)=7(x+2)
x - 3x + x = 7x + 14
2x - 3 = 7x + 14
2x - 7x = 14 + 3
-5x = 17
x = ¹⁷/-5
nota: avísame si tenés dudas