Explicación paso a paso:
√15 - √5 / √5
√ 15 - 1
Respuesta = -1 + √15
bais xd
Respuesta:
[tex]\boxed{\mathfrak{\frac{\sqrt{15-\sqrt{5}}{\sqrt{5}}=\sqrt{3}-1}}[/tex]
[tex]\ffac{\sqrt{15}-\sqrt{5}}{\sqrt{5}}[/tex]
Usemos la siguiente propiedad:
[tex]\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}\\\\\sqrt{15}=\sqrt{(3)(5)}=\sqrt{3}\sqrt{5}\\\\\frac{\sqrt{15-\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{3}\sqrt{5}-\sqrt{5}}{\sqrt{5}}=\\\\=\frac{\sqrt{3}\sqrt{5}}{\sqrt{5}}-\frac{\sqrt{5}}{\sqrt{5}}=\sqrt{3}-1[/tex]
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Verified answer
Explicación paso a paso:
√15 - √5 / √5
√ 15 - 1
Respuesta = -1 + √15
bais xd
Respuesta:
[tex]\boxed{\mathfrak{\frac{\sqrt{15-\sqrt{5}}{\sqrt{5}}=\sqrt{3}-1}}[/tex]
Explicación paso a paso:
[tex]\ffac{\sqrt{15}-\sqrt{5}}{\sqrt{5}}[/tex]
Usemos la siguiente propiedad:
[tex]\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}\\\\\sqrt{15}=\sqrt{(3)(5)}=\sqrt{3}\sqrt{5}\\\\\frac{\sqrt{15-\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{3}\sqrt{5}-\sqrt{5}}{\sqrt{5}}=\\\\=\frac{\sqrt{3}\sqrt{5}}{\sqrt{5}}-\frac{\sqrt{5}}{\sqrt{5}}=\sqrt{3}-1[/tex]