Respuesta:
[tex]x\geq \frac{6y}{5}-15 \\[/tex]
Explicación paso a paso:
[tex]\frac{x}{3} +\frac{2y}{5} \leq 5\\\frac{x}{3}\leq 5-\frac{2y}{5} \\x\leq 15-\frac{6y}{5} \\x\geq \frac{6y}{5}-15[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Respuesta:
[tex]x\geq \frac{6y}{5}-15 \\[/tex]
Explicación paso a paso:
[tex]\frac{x}{3} +\frac{2y}{5} \leq 5\\\frac{x}{3}\leq 5-\frac{2y}{5} \\x\leq 15-\frac{6y}{5} \\x\geq \frac{6y}{5}-15[/tex]