Question

∧5log 1 per 125+∧4log 1 per 64+∧3log 1 per 27-2log16=

Answer 1

(^5Log1/125)+(⁴Log1/64)+(³Log1/27)-(²Log16)
= (^5Log5^-5)+(⁴Log4^-3)+(³Log3^-3)-(²Log2⁴)
= (-1/5)(^5Log5)+(-1/3)(⁴Log4^-3)+(-1/3)(³Log3^-3)-(1/4)(²Log2⁴)
=(-5)+(-3)+(-3)-(4)
=-5-3-3-4
=-15