Jumlah kelereng A terhadap kelereng B = 3/4.Kelereng B terhadap C = 2/5.Jumlah kelereng mereka bertiga 102 butir.Berapa banyak kelereng mereka masing-masing?Tolong pakai cara ya!
Marinska
3 : 4, 2 : 5 4 / 2 = 2 5 x 2 =10 3 : 4 : 10 a = 102/(3+4+10) x 3 = 102/17 x 3 = 6 x 3 = 18 b = 6 x 4 = 24 c = 6 x 10 = 60
4 / 2 = 2
5 x 2 =10
3 : 4 : 10
a = 102/(3+4+10) x 3 =
102/17 x 3 = 6 x 3 = 18
b = 6 x 4 = 24
c = 6 x 10 = 60
a + b + c = 102
18 + 24 + 60 = 102
#maaf rumusnya kurang jelas