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mcz HCl = 36,5 u
mCa = 40 u
Ca + 2 HCl ---> CaCl2 + H2
5g ---x
40g---2*36,5
___________
x= 2*36,5*5/40 = 9,125g <= masa substancji
Cp = 15%
9,125 - 15%
x---------100%
__________
x= 9,125*100/15 = 60,8g <= masa roztworu