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x - 3y = 1 ==> x = 1 + 3y....1
x² + y² = 5.......2
xy = 2.......3
subs 1 ke 3
x = 1 + 3y
(1 + 3y)y = 2
y + 3y² = 2
3y² + y - 2 = 0
(3y - 2)(y + 1) = 0
3y - 2 = 0 atau y + 1 = 0
y = atau y = -1
untuk y =
xy = 2
x. = 2
x = 3
untuk y = -1
xy = 2
x.(-1) = 2
x = -2
5x + 5y = 5(x +y).. kalo ngambil x = -2 dan y = -1 didapat nilai -15