Un medio por Entre parentesis tres cuartos x menos un tercio cierra parentesis mas x/4 = 1

August 2018 1 33 Report

Un medio por Entre parentesis tres cuartos x menos un tercio cierra parentesis mas x/4 = 1 - x-2/5

LuffyPeru RESOLVER:

$\frac{1}{2}\cdot \left(\frac{3}{4}x-\frac{1}{3}\right)+\frac{x}{4}=1-x-\frac{2}{5}$
$\frac{1}{2}\left(\frac{3}{4}x-\frac{1}{3}\right)+\frac{x}{4}=\frac{1}{1}-\frac{2}{5}$
$\frac{1}{2}\left(\frac{3}{4}x-\frac{1}{3}\right)+\frac{x}{4}=\frac{1\cdot \:5}{5}-\frac{2}{5}$
$\frac{1}{2}\left(\frac{3}{4}x-\frac{1}{3}\right)+\frac{x}{4}=\frac{1\cdot \:5-2}{5}$
$\frac{1}{2}\left(\frac{3}{4}x-\frac{1}{3}\right)+\frac{x}{4}=-x+\frac{3}{5}$
$\frac{1}{2}\left(\frac{3}{4}x-\frac{1}{3}\right)+\frac{x}{4}+x=-x+\frac{3}{5}+x$
$\frac{39x-4}{24}=\frac{3}{5}$
$\frac{24\left(39x-4\right)}{24}=\frac{3\cdot \:24}{5}$
$39x-4=\frac{72}{5}$
$39x-4+4=\frac{72}{5}+4$
$39x=\frac{92}{5}$
$\frac{39x}{39}=\frac{\frac{92}{5}}{39}$
$x=\frac{92}{195}$

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