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⁵log 3= q . ,=maka ³log 5 = 1/q
⁴⁵log 3/5 = ⁴⁵log 3 - ⁴⁵log 5
= 1/³log 45 - 1/⁵log 45
= 1/ (³log 3² +³log 5) - 1/(⁵log3² + ⁵log 5)
= 1/(2 + 1/q) - 1/ (2q +1)
= q/(2q+1) - 1(2q + 1)
= (q -1)/ (2q +1)