Respuesta:
=(5a2b+−1)(5a2b+1)
=(5a2b)(5a2b)+(5a2b)(1)+(−1)(5a2b)+(−1)(1)
=25a4b2+5a2b−5a2b−1
=25a4b2−1
Explicación paso a paso:
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Solucion :
(5a2b−1)(5a2b+1)
=(5a2b+−1)(5a2b+1)
=(5a2b)(5a2b)+(5a2b)(1)+(−1)(5a2b)+(−1)(1)
=25a4b2+5a2b−5a2b−1
=25ab2−14
Espero haberte ayudado.
Verified answer
Respuesta:
=(5a2b+−1)(5a2b+1)
=(5a2b)(5a2b)+(5a2b)(1)+(−1)(5a2b)+(−1)(1)
=25a4b2+5a2b−5a2b−1
=25a4b2−1
Explicación paso a paso: