Question

Tentukan bilangan pokoknya logaritma berikut ini,jika diketahui :
1. log 216 = 3
2. log 81 =1 1/3
3. log √(3) = 2
4. log 1/ √5(100) = 1/5

Answer 1

1) ⁿ log 216 = 3
n³ = 216  ---> n = 6
 .
2) ⁿlog 81 = 4/3
n^(4/3) =81
n =  81^(3/4) = (3)^4(3/4)
n = 3^3 = 27
.
3) ⁿ log √3 = 2
n² = √3
n =  ∜3
.
4) ⁿ log 1/ (100^1/5) = 1
n = 100^-(1/5) 
n = 10^-(2/5)