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tempat wisata = y
makan = z
paket 1
4x + 3y + 5z = a
paket 2
3x + 4y + 7z = b
paket 3
5x + 4y + 0z = c
(4 3 5) (x) = (a)
(3 4 7) (y) = (b)
(5 4 0) (z) = (c)
(a) = {4(400.000) + 3(80.000) + 5(90.0000)}
(b) = {3(400.000) + 4(80.000) + 7(90.0000)}
(c) = {5(400.000) + 4(80.000) + 0(90.0000)}
(a) = (1.600.000 + 240.000 + 450.000)
(b) = (1.200.000 + 320.000 + 630.000)
(c) = (2.000.000 + 320.000 + 0)
(a) = (2.290.000)
(b) = (2.150.000)
(c) = (2.320.000)
paket 1
4x + 3y + 5z = 2.290.000
paket 2
3x + 4y + 7z = 2.150.000
paket 3
5x + 4y + 0z = 2.320.000
jadi paket yang termurah adalah paket 2