Sea g(x)=4x-3sobre2x-6 halla g(-3/5)
beto2347
Nos pide hallar, solamente debemos sustituir el valor de -3/5 en donde esta x y encontraremos ese valor
![[tex]g(x) = \frac{4x - 3}{2x - 6} ,sustituyendo \\ \\ g( \frac{-3}{5} ) = \frac{4( \frac{-3}{5}) - 3 )}{2(\frac{-3}{5}) - 6}, simplificando, \\ \\ g( \frac{-3}{5} ) = \frac{ \frac{-12}{5}- \frac{15}{5} }{ \frac{-6}{5} - \frac{30}{5} } , pasamos, los, enteros, a, fracciones, y, operamos \\ \\ g( \frac{-3}{5} ) = \frac{ \frac{-27}{5} }{ \frac{-36}{5} }, extremos, por, extremos, medios, por, medios, nos, da \\ \\ g( \frac{-3}{5} ) = \frac{3}{4}, ya, simplificado, al, maximo](https://tex.z-dn.net/?f=%5Btex%5Dg%28x%29+%3D+%5Cfrac%7B4x+-+3%7D%7B2x+-+6%7D+%2Csustituyendo+%5C%5C+%5C%5C+g%28+%5Cfrac%7B-3%7D%7B5%7D+%29+%3D+%5Cfrac%7B4%28+%5Cfrac%7B-3%7D%7B5%7D%29+-+3+%29%7D%7B2%28%5Cfrac%7B-3%7D%7B5%7D%29+-+6%7D%2C+simplificando%2C+%5C%5C+%5C%5C+g%28+%5Cfrac%7B-3%7D%7B5%7D+%29+%3D+%5Cfrac%7B+%5Cfrac%7B-12%7D%7B5%7D-+%5Cfrac%7B15%7D%7B5%7D+%7D%7B+%5Cfrac%7B-6%7D%7B5%7D+-+%5Cfrac%7B30%7D%7B5%7D+%7D+%2C+pasamos%2C+los%2C+enteros%2C+a%2C+fracciones%2C+y%2C+operamos+%5C%5C+%5C%5C+g%28+%5Cfrac%7B-3%7D%7B5%7D+%29+%3D+%5Cfrac%7B+%5Cfrac%7B-27%7D%7B5%7D+%7D%7B+%5Cfrac%7B-36%7D%7B5%7D+%7D%2C+extremos%2C+por%2C+extremos%2C+medios%2C+por%2C+medios%2C+nos%2C+da+%5C%5C+%5C%5C+g%28+%5Cfrac%7B-3%7D%7B5%7D+%29+%3D+%5Cfrac%7B3%7D%7B4%7D%2C+ya%2C+simplificado%2C+al%2C+maximo "[tex]g(x) = \frac{4x - 3}{2x - 6} ,sustituyendo \\ \\ g( \frac{-3}{5} ) = \frac{4( \frac{-3}{5}) - 3 )}{2(\frac{-3}{5}) - 6}, simplificando, \\ \\ g( \frac{-3}{5} ) = \frac{ \frac{-12}{5}- \frac{15}{5} }{ \frac{-6}{5} - \frac{30}{5} } , pasamos, los, enteros, a, fracciones, y, operamos \\ \\ g( \frac{-3}{5} ) = \frac{ \frac{-27}{5} }{ \frac{-36}{5} }, extremos, por, extremos, medios, por, medios, nos, da \\ \\ g( \frac{-3}{5} ) = \frac{3}{4}, ya, simplificado, al, maximo")
[/tex]
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Thanks 1
Roberta11
muchas gracias pero cuando lo resolvemos nos da resultado diferentes por eso pedimos ayuda
beto2347
perdon es que no se habia insertado la ecuacion