Oblicz masę hydratow :
Siarczan (VI) magnezu - woda 1/3
azotan (V) magnezu - woda 1/6
chlorek miedzi (II) - woda 1/5
Siarczan (VI) magnezu - woda 1/3
azotan (V) magnezu - woda 1/6
chlorek miedzi (II) - woda 1/5
exxxq2012
![24u+32u+64u+3*18u=24u+32u+64u+54=174u\\[tex]m_{Mg(NO_3)_2*6H_2O}=1*24u+2*14u+6*16u+6*18u=](https://tex.z-dn.net/?f=24u%2B32u%2B64u%2B3%2A18u%3D24u%2B32u%2B64u%2B54%3D174u%5C%5C%5Btex%5Dm_%7BMg%28NO_3%29_2%2A6H_2O%7D%3D1%2A24u%2B2%2A14u%2B6%2A16u%2B6%2A18u%3D "24u+32u+64u+3*18u=24u+32u+64u+54=174u\\[tex]m_{Mg(NO_3)_2*6H_2O}=1*24u+2*14u+6*16u+6*18u=")
![=24u+28u+96u+108u=256u\\[tex]m_{CuCl_2*5H_2O}=1*64u+2*35,5u+5*18u=64u+71u+90u=225](https://tex.z-dn.net/?f=%3D24u%2B28u%2B96u%2B108u%3D256u%5C%5C%5Btex%5Dm_%7BCuCl_2%2A5H_2O%7D%3D1%2A64u%2B2%2A35%2C5u%2B5%2A18u%3D64u%2B71u%2B90u%3D225 "=24u+28u+96u+108u=256u\\[tex]m_{CuCl_2*5H_2O}=1*64u+2*35,5u+5*18u=64u+71u+90u=225")
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