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=> (5x)² - 6(5x) + 5 = 0
Misal : 5x = y
=> y² - 6y + 5 = 0
(y-1)(y-5) = 0
y = 1 atau y = 5
y = 1
5x = y
5x = 1
x = 1/5
y = 5
5x = y
5x = 5
x = 1
=> {1/5, 1}