Aljabar
Pemfaktoran
soal 1
x/3 + 3/x = 10/3
kedua ruas kalikan (3x)
x² + 9 = 10x
x² - 10x + 9 = 0
(x - 1)(x - 9) = 0
x - 1 = 0 atau x - 9 = 0
x = 1 atau x = 9
Nilai x :
1 dan 9
•
1/x + 1/(x - 1) = 7/12
samakan penyebut → x(x - 1)
(x - 1 + x)/(x(x - 1)) = 7/12
kali silang
12(2x - 1) = 7(x² - x)
24x - 12 = 7x² - 7x
7x² - 7x - 24x + 12 = 0
7x² - 31x + 12 = 0
(7x - 3)(x - 4) = 0
7x - 3 = 0 atau x - 4 = 0
x = 3/7 atau x = 4
3/7 dan 4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Aljabar
Pemfaktoran
soal 1
x/3 + 3/x = 10/3
kedua ruas kalikan (3x)
x² + 9 = 10x
x² - 10x + 9 = 0
(x - 1)(x - 9) = 0
x - 1 = 0 atau x - 9 = 0
x = 1 atau x = 9
Nilai x :
1 dan 9
•
1/x + 1/(x - 1) = 7/12
samakan penyebut → x(x - 1)
(x - 1 + x)/(x(x - 1)) = 7/12
kali silang
12(2x - 1) = 7(x² - x)
24x - 12 = 7x² - 7x
7x² - 7x - 24x + 12 = 0
7x² - 31x + 12 = 0
(7x - 3)(x - 4) = 0
7x - 3 = 0 atau x - 4 = 0
x = 3/7 atau x = 4
Nilai x :
3/7 dan 4