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mol NH₃ = 50 x 0,1 = 5 mmol
mol HCl = 50 x 0,1 = 5 mmol
karena mol asam kuat (HCl) dan mol NH₃ (basa lemah) sama, maka terjadi sistem hidrolisis garam.
NH₃ + HCl → NH₄Cl
mol NH₄Cl (garam) yang terbentuk = 5 mmol
M garam = mol/volume total
M garam = 5/(50+50) = 5/100
M garam = 0,05 M
[H⁺] = √Kw/Kb • M garam
[H⁺] = √10⁻¹⁴/1,8 x 10⁻⁵ • 0,05
[H⁺] = √2,77 x 10⁻¹¹
[H⁺] = 5,27 x 10⁻⁶
pH = -log [H⁺]
pH = -log [5,27 x 10⁻⁶]
pH = 6 - log 5,27
Jadi, pH larutan adalah 6 - log 5,27