PROCEDIMIENTO:
[tex]5x-6>4\\\\5x-6+6>4+6\\\\5x>10\\\\\frac{5x}{5}>\frac{10}{5}\\\\x>2[/tex]
Resultado: [tex]x>2[/tex]
Atte: Sabius95
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Verified answer
PROCEDIMIENTO:
[tex]5x-6>4\\\\5x-6+6>4+6\\\\5x>10\\\\\frac{5x}{5}>\frac{10}{5}\\\\x>2[/tex]
Resultado: [tex]x>2[/tex]
Atte: Sabius95