Question

Moohon di bantu kakak!
Bila sin a= 5/13 dan cos b=4/5 tentukan nillai tga.tgb=...

Answer 1

sin a = 5/13 ---------> y/r

y = 5 , r = 13

mencari x

x² = r² - y²

x² = 13² - 5²

x² = 169 - 25

x² = 144

x = √144 = 12

cos a = x/r = 12/13

cos b = 4/5 --------> x/r

x = 4 , r = 5

mencari y

y² = r² - x²

y² = 5² - 4²

y² = 25 - 16

y² = 9

y = √9 = 3

sin b = y/r = 3/5

tan a . tan b

= sin a/cos a . sin b/cos b

= 5/13 : 12/13 x 3/5 : 4/5

= 5/13 . 13/12 x 3/5 . 5/4

= 5/12 . 3/4

= 15/48

= 5/16

Moga membantu...

Answer 2

5/16.....................