Invers Fungsi
f(x) = 3x
g(x) = x + 3
(fog)(x)
= f(g(x))
= f(x + 3)
= 3(x + 3)
= 3x + 9
(fog)(x) = y = 3x + 9
3x = y - 9
x = (fog)⁻¹ (y) = (y - 9)/3
Inver fungsi :
(fog)⁻¹ (x) = (x - 9)/3
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Invers Fungsi
f(x) = 3x
g(x) = x + 3
(fog)(x)
= f(g(x))
= f(x + 3)
= 3(x + 3)
= 3x + 9
(fog)(x) = y = 3x + 9
3x = y - 9
x = (fog)⁻¹ (y) = (y - 9)/3
Inver fungsi :
(fog)⁻¹ (x) = (x - 9)/3