Question

6. Pada Δ ABC, diketahui sudut A = 3/2 sudut B dan
sudut B= 4/5 sudut C. Besar sudut C = ....
A. 48°
C. 64
B. 60°
D. 72°
​

Answer 1

Jawab:

Penjelasan dengan langkah-langkah:

S(b) = 4/5 x s(c)

S(a) = 3/2 x s(b)

= 3/2 x 4/5 s(c)

= 12/10 x s(c) = 6/5 x s(c)

S(a) + s(b) + s(c) = 180

6/5 s(c) + 4/5 s(c) + s(c) = 180

3 s(c) = 180

s(c) = 180/3

= 60 derajat

Smg membantu

Answer 2

A = 3/2 B --> A : B = 3 : 2 --> 6 : 4

B = 4/5C ---> B : C = 4 : 5

A : B : C = 6 : 4 : 5

A + B + C = 180°

jadi

sudut C =

(5/(6+4+5)) x 180° =

(5/15) x 180° =

1/3 x 180° =

60°